If the cell potential value is negative for a cell constructed by attaching a standard hydrogen electrode to another half-cell,then the other half-cell will be:
$(i)$ Anode or cathode?
$(ii)$ Positive or negative?
$(iii)$ On left side or right side?
$(i)$ Anode or cathode?
$(ii)$ Positive or negative?
$(iii)$ On left side or right side?
(A) The cell potential $E_{cell}$ is given by $E_{cell} = E_{cathode} - E_{anode}$.
Given that the standard hydrogen electrode $(SHE)$ has a potential of $0.00 \ V$,if the cell potential is negative,it implies that the potential of the other half-cell is lower than the $SHE$.
$(i)$ Since the other half-cell has a lower potential,it acts as the $Anode$ (oxidation occurs here).
$(ii)$ The $Anode$ in a galvanic cell is the $Negative$ electrode.
$(iii)$ By convention,the $Anode$ is placed on the $Left$ side of the cell diagram.
Given that the standard hydrogen electrode $(SHE)$ has a potential of $0.00 \ V$,if the cell potential is negative,it implies that the potential of the other half-cell is lower than the $SHE$.
$(i)$ Since the other half-cell has a lower potential,it acts as the $Anode$ (oxidation occurs here).
$(ii)$ The $Anode$ in a galvanic cell is the $Negative$ electrode.
$(iii)$ By convention,the $Anode$ is placed on the $Left$ side of the cell diagram.
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$Fe^{3+} + e^- \to Fe^{2+}; E^o = 0.771 \ V$
$I_2 + 2e^- \to 2I^{-}; E^o = 0.536 \ V$
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$Zn_{(s)} \mid Zn^{2+}_{(1M)} \parallel KCl_{(sat)} \mid Hg_2Cl_{2(paste)} \mid Hg$
$E^{\circ}_{cell} = 1.007 \ V$ and $E^{\circ}_{calomel} = 0.242 \ V$
What is the standard potential of $Zn$ (in $V$)?
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View SolutionCalculate the standard cell potential $(E_{cell}^{o})$ for the following electrochemical cells:
$(i)$ $Al_{(s)}|Al_{(1M)}^{3+}||Cu_{(1M)}^{2+}|Cu_{(s)}$
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$($ Given: $E_{Al^{3+}|Al}^{o} = -1.66 \ V$,$E_{Zn^{2+}|Zn}^{o} = -0.76 \ V$,$E_{Cu^{2+}|Cu}^{o} = 0.34 \ V$,$E_{Ag^{+}|Ag}^{o} = 0.80 \ V$ $)$
$(i)$ $Al_{(s)}|Al_{(1M)}^{3+}||Cu_{(1M)}^{2+}|Cu_{(s)}$
$(ii)$ $Al_{(s)}|Al_{(1M)}^{3+}||Zn_{(1M)}^{2+}|Zn_{(s)}$
$(iii)$ $Al_{(s)}|Al_{(1M)}^{3+}||Ag_{(1M)}^{+}|Ag_{(s)}$
$($ Given: $E_{Al^{3+}|Al}^{o} = -1.66 \ V$,$E_{Zn^{2+}|Zn}^{o} = -0.76 \ V$,$E_{Cu^{2+}|Cu}^{o} = 0.34 \ V$,$E_{Ag^{+}|Ag}^{o} = 0.80 \ V$ $)$
Medium
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